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"license:ccbysa", "transcluded:yes", "source[1]-chem-36454", "licenseversion:40", "author@Steven Farmer", "author@Dietmar Kennepohl", "author@William Reusch", "author@Henry Jakubowski" ], https://chem.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fchem.libretexts.org%2FCourses%2FSmith_College%2FOrganic_Chemistry_(LibreTexts)%2F25%253A_Biomolecules-_Carbohydrates%2F25.03%253A_Depicting_Carbohydrate_Stereochemistry_-_Fischer_Projections, \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), Below are two different representations of (R)-glyceraldehyde, the smallest sugar molecule (also called. [closed], http://www.chemeddl.org/resources/stereochem/definitions17.htm, http://www.chemeddl.org/resources/stereochem/definitions16.htm. So you could do the same There are eight stereoisomers of 2,3,4,5-tetrahydroxypentanal, a group of compounds referred to as the aldopentoses. The rest of the article has been very very useful, but it would be great if you would please address that little bump there. is there an easier way to do this? Now, if I wanted to draw have my Fischer projection and your aldehyde is gonna get a one and then two, three, four, in terms of numbering your carbon chain. draw the wedge and dash structure of a monosaccharide, given its Fischer projection or a molecular model. Thus carbon 1 (O,O,H) takes priority over carbon 3 (O,C,H) . Creative Commons Attribution/Non-Commercial/Share-Alike. The structure must not be flipped over or rotated by 90. Otherwise, the title does not match the questions, and it would be difficult to find your second question. Make certain that you can define, and use in context, the key term below. Horizontal lines on a Fisher projection represent a group coming out of the page (wedges). Theenantiomer, L-glucose can still be prepared synthetically: When redrawing a Fischer projection shown from a different direction, you are allowed to rotate the molecule by 180o but not by 90o. absolutel configuration, I look at the fact that My textbook says "High priority group lies at the top of the vertical line. Well, that's oxygen versus carbon, versus a carbon over here in my carbonyl, so obviously oxygen's going to win, so we can assign oxygen a number one priority since it has the highest atomic number. We now view the molecule with C-1 at the top and with all chiral carbons closest to our eye. For this, we are going to draw the molecule and simply show all the bonds with plane solid lines, keeping in mind that the horizontal groups are pointing towards you and the ones on the vertical line are pointing away from you: So, how do you remember which ones are pointing towards you? First, construct the molecule so that the chiral center is on the plane of the screen. An alternative way to represent stereochemistry is the Fischer Projection, which was first used by the German chemist Emil Fischer. It can be any right or left unless specified in the question. What is the relationship between these two structures? So at carbon two, what do I have? In a Fischer projection drawing, the four bonds to a chiral carbon make a cross with the carbon atom at the intersection of the horizontal and vertical lines. Fisher projections show sugars in their open chain form. These atoms will be designated with dashed lines like those in Figure B by number 2 and 6. The zig-zag will have the methyl on the bottom-left side and the ethyl group on the right side respectively: Now, to transform the bond-line into a Fischer projection, we can look at from the top such that the methyl group goes on the top of the Fischer projection: Remember, to flip the bond between the carbons in order to have the horizontal groups as wedge lines before drawing out the Fischer projection: Below are some practice problems converting between Bond-Line, Newman, and Fischer projections. rev2023.3.1.43269. Show transcribed image text. How can I convert R-3-methylhexane-3-ol to a Fisher projection? Now that we have our Dashed- Wedged Line Structure, we can convert it to a Fischer Projection. To make a Fischer Projection, it is easier to show through examples than through words. molecule in a mirror. Show transcribed image text. By following specific rules for drawing these projections, one can depict complex carbohydrates such as glucose and fructose in a way that conveys their structural information. The long answer is, well, really long and I put under the tips section. The reason being is that it allows us to only focus on one central carbon, which make things a little bit easier. Which of the following wedge-and-dash structures represents the Fischer projection shown below? The structure A represents Fischer Projection of a compound. The wedge and hatched line notations we have been using are effective, but can be troublesome when applied to compounds having many chiral centers. it's going around clockwise, therefore this is the R Let's assign absolute configurations to one of these stereoisomers, so let's just choose the first one, A, so we've been talking about A, and let's go ahead and Or, you can look at it this way; it depends on whether you put the group on the left/right in the bond-line structure on the top or on the bottom of the Fischer projection. Drift correction for sensor readings using a high-pass filter, Ackermann Function without Recursion or Stack. Lets start with the conversion between bond-line structures and Newman projections. After completing this section, you should be able to. projection for R lactic acid, so this is R lactic acid. Don't worry, you're not the only one confused by this. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. Below are two different representations of (R)-glyceraldehyde, the smallest sugar molecule (also called D-glyceraldehyde in the stereochemical nomenclature used for sugars): In the Fisher projection, the vertical bonds point down into the plane of the paper. I look at the first atom connected to that chirality center. Since there are three chiral centers in this constitution, we should expect a maximum of 23 stereoisomers. Direct link to Tim's post Excellent question, Luke., Posted 10 years ago. The two vertical bonds are directed behind the central carbon (away from the viewer). This means, for example, when you are converting a Fischer projection to a bond-line, you can simply draw the zig-zag with the correct number of carbons and add the groups by randomly assigning them wedge and dash notation. It seems like each one needs a different technique to align to the correct R or S config. If the lowest priority group (often a hydrogen) is on a vertical bond, the configuration is given directly from the relative positions of the three higher-ranked substituents. The mirror-image formula, where x = CO2H, y = CH3, a = OH & b = H, would, of course, represent (S)-(+)-lactic acid. just make it much easier when you're working with carbohydrates. So too that in a Fischer projection, each chirality center is drawn individually. center in lactic acid, it's an sp three hybridized carbon with four different Thank you. Compound A I'm gonna stare down, in the stereochemical nomenclature used for sugars): Below are three representations of the open chain form of. The aldopentose structures drawn above are all diastereomers. wedge-and-dash (uncountable) (chemistry) A method of representing the three-dimensional structure of a molecule in which simple lines represent bonds in the plane of the image, wedge-shaped lines represent bonds towards the viewer, and dashed lines represent bonds away from the viewer. Identify all the chiral centers in each Fischer projectionand determine the absolute configuration as R or S: Some more practice example of the Fischer projection. By joining Chemistry Steps, you will gain instant access to the, How to Determine the R and S configuration, The R and S Configuration Practice Problems, Diastereomers-Introduction and Practice Problems, E and Z Alkene Configuration with Practice Problems, Enantiomers Diastereomers the Same or Constitutional Isomers with Practice Problems, Enantiomeric Excess (ee): Percentage of Enantiomers from Specific Rotation with Practice Problems, Calculating Enantiomeric Excess from Optical Activity, Fischer Projections with Practice Problems, Resolution of Enantiomers: Separate Enantiomers by Converting to Diastereomers. Fischer projections were originally proposed for the depiction of carbohydrates and used by chemists, particularly in organic chemistry and biochemistry. b) Label all stereocenters as R or S. c) Indicate any pair of enantiomers, diastereomers and the meso compound if present. Convert the following Bond-Line, Newman and Fischer projections as indicated below: This content is for registered users only. This carboxylic acid functional group, this is the top of my head right here, then that would make this go at the top of what I'm looking at, and so, that is going Direct link to Tim's post You must remember that Ja, Posted 10 years ago. 2 years ago. Black wedges represent chemical bonds coming toward you, while dashed lines are for bonds that extend back behind the surface .We must view a wedge-dash formula from the correct angle to convert it to a Fischer projection. is actually coming out at me, so in the little trick I showed you in the earlier video, if the hydrogen is coming out at me, all you have to do is reverse it. Well, if I think about, this is my chirality center, what are the atoms directly And if you do that, you will find that it is also R. So you can go ahead and and draw my aldehyde. Start by imagining yourself looking directly at the central carbon from the left side as shown in Figure C. It should look something like Figure D. Now take this Figure D and flatten it out on the surface of the paper and you should get an image of a cross. possible stereoisomers for this carbohydrate. The point of intersection between the horizontal and vertical lines represents the central carbon. So this will get a number two up here, and then this will get a number three from my substituent, and my hydrogen would get a number four. The direction is usually given with an eye symbol or an arrow. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. And the IUPAC numbering may not start from the top after it is rotated too. Label all stereocenters R or S. 25.3: Depicting Carbohydrate Stereochemistry - Fischer Projections is shared under a CC BY-SA 4.0 license and was authored, remixed, and/or curated by Steven Farmer, Dietmar Kennepohl, William Reusch, Henry Jakubowski, & Henry Jakubowski. Watch the video on Cahn-Ingold-Prelog System for those rules. The reason for this is the fact that the absolute configuration of the chirality centers must be retained since it is the same molecule. There are eight stereoisomers of 2,3,4,5-tetrahydroxypentanal, a group of compounds referred to as the aldopentoses (aldo- since the oxidized carbon is an aldehyde and -pentose since the molecules contain 5 carbons). In a Fischer projection drawing, the four bonds to a chiral carbon make a cross with the carbon atom at the intersection of the horizontal and vertical lines. . Let's go ahead and make it to Well, you can remember that Fischer projections like you and they are coming to give you a hug with open arms: Or, you look at the Fischer projection like you are in the gym and need to grab the molecule. Remember each chirality center is determined (R) or (S) individually. Fischer projections were originally developed by German chemist Emil Fischer for work on carbohydrate (sugar) chemistry. I know a Fischer projection tells me that if it's a horizontal line, everything's coming out at me, so my OH is coming out at me, and my hydrogen is coming out at me. The Fisher structures of the most common monosaccharides (other than glyceraldehyde and dihydroxyacetone), which you will encounter most frequently are shown below. Wedge and Dash Projection. 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